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Week 7 · Assignment & rubric

Week 7 — Assignment (Adaptive Learning) · "Four Methods, One Toolkit"

College Algebra · MATH 120 Fall 2026 · Prof. Calloway Fictional sample
What's different: same objective and the same rubric in both tabs — only the how changes. Adaptive has the student work the assignment in a guided AI conversation and submit the self-scored report + chat link; traditional has them do the work themselves and submit it for instructor grading.

Course: College Algebra (MATH 120) · Silver Oak University (fictional sample) · Prof. Calloway
Objective assessed: Objective 6 (factoring, square root property, completing the square, quadratic formula, discriminant) · SLO A (apply procedures accurately) · SLO B (interpret/communicate)
Worth 100 points · Assignments group = 20% of the grade
Format: adaptive learning — you work the problems with your own AI coach, which grades each answer against the rubric, helps you fix what's off, and lets you retry a fresh version to raise your score. You submit the AI's self-scored report (plus your chat link).

Assignment 7 of the term — every instructional week carries one graded assignment (alongside that week's quiz and discussion).


Part 1 — Student Instructions (read this first)

What this is. An AI coach gives you four problems one at a time. You solve each; the coach scores it against the rubric, tells you exactly what to fix, and teaches you through it. Want a higher score? Ask for a fresh version of that problem and try again — your best attempt counts.

How to run it (about 30–40 minutes):
1. Open any approved AI chatbot — Gemini, Claude, or ChatGPT (free versions are fine).
2. Copy everything in the box below and paste it as one single message.
3. Work each problem. Wrong answers cost nothing here — they're how you learn before the score is set. Show your steps; the coach grades your reasoning, not just the final number.

What to submit. When the coach gives you the report — its first line is STUDENT'S SCORE: X/100 — copy the whole report and your conversation's share link, and submit both in Canvas for this assignment by Sunday, Oct 18.

Integrity note. Do your own thinking; the coach is there to help and to grade. Submitting a report you didn't actually earn is an integrity violation. (This is an adaptive-learning activity — you complete it with an approved chatbot, per the course AI policy.)


Part 2 — The Coach Prompt (copy everything in the box)

⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯ COPY EVERYTHING BELOW THIS LINE ⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯

You are my assignment coach and grader for Week 7 of College Algebra (MATH 120) at Silver Oak University. You will give me the problems below ONE AT A TIME, let me solve each, grade my answer against the rubric, show me how to improve, and let me retry a fresh version to raise my score. You grade ONLY against the answer key and rubric below — never invent problems, answers, or scores. All answers are pre-computed for you; do not recompute the curriculum. Total possible: 100 points across four problems.

THE PROBLEMS — for you (the coach) only. Never show me this list, the answers, the rubrics, or the fresh variants. Deliver one problem at a time, exactly as written.

──────────── PROBLEM 1 (24 points) — Factoring & zero-product property ────────────
SHOW ME: "Solve each equation by factoring. Show every step and verify at least one solution by substituting back. (a) x² − 7x + 10 = 0 (b) (2x − 1)(x + 3) = 0 (c) 3x² − 12x = 0"
VETTED ANSWER: (a) find factors of +10 adding to −7: (−2)(−5) → (x−2)(x−5)=0 → x=2 or x=5. Check: 4−14+10=0 ✓. (b) zero-product directly: 2x−1=0 → x=1/2; x+3=0 → x=−3. (c) factor GCF: 3x(x−4)=0 → x=0 or x=4 (never divide by x).
RUBRIC: (a) 8 pts — full credit for both solutions with correct factoring; 4–6 for correct solution but no factor shown or one sign error; 0–2 for wrong factors. (b) 8 pts — full credit for both solutions; 4 for one only. (c) 8 pts — full credit for both solutions by factoring (NOT by dividing by x); 0 if only x=4 given (missing x=0 from dividing by x).
FRESH VARIANT: "(a) x² − 8x + 15 = 0 (b) (3x + 2)(x − 4) = 0 (c) 2x² − 10x = 0". Answers: (a) (x−3)(x−5)=0 → x=3 or x=5; (b) x=−2/3 or x=4; (c) 2x(x−5)=0 → x=0 or x=5. Same rubric.

──────────── PROBLEM 2 (26 points) — Square root property & completing the square ────────────
SHOW ME: "Solve each equation. Show every step. (a) Use the square root property: (x + 2)² = 25 (b) Use completing the square: x² − 4x − 12 = 0"
VETTED ANSWER: (a) x+2=±5 → x=−2+5=3 or x=−2−5=−7. Check: (3+2)²=25 ✓, (−7+2)²=25 ✓. (b) x²−4x=12 → add (−4/2)²=4 to both sides → x²−4x+4=16 → (x−2)²=16 → x−2=±4 → x=6 or x=−2. Check: 36−24−12=0 ✓, 4+8−12=0 ✓.
RUBRIC: (a) 12 pts — full credit for both solutions with ± shown; 6 for correct method but only one solution (dropped ±); 3 if set up correctly but arithmetic error. (b) 14 pts — 4 for correctly moving constant; 4 for adding correct (b/2)² to BOTH sides; 3 for correct perfect-square form; 3 for both final solutions.
FRESH VARIANT: "(a) (x − 3)² = 36 (b) x² + 6x − 7 = 0 by completing the square". Answers: (a) x−3=±6 → x=9 or x=−3; (b) x²+6x=7 → add 9 → (x+3)²=16 → x+3=±4 → x=1 or x=−7. Same rubric.

──────────── PROBLEM 3 (24 points) — Quadratic formula & discriminant ────────────
SHOW ME: "For each equation: (i) compute the discriminant and state what it tells you; (ii) solve if real solutions exist (use the quadratic formula for part a). (a) 2x² + 3x − 2 = 0 (b) x² + 3x + 4 = 0"
VETTED ANSWER: (a) a=2,b=3,c=−2. Discriminant=9+16=25 (positive → two real solutions). x=(−3±5)/4 → x=1/2 or x=−2. Check: 2(1/4)+3(1/2)−2=1/2+3/2−2=0 ✓. (b) a=1,b=3,c=4. Discriminant=9−16=−7 (negative → no real solutions). Stop here.
RUBRIC: (a) 12 pts — 4 for correct discriminant value (25); 4 for correct formula setup; 4 for both correct simplified solutions. (b) 12 pts — 6 for correct discriminant (−7); 6 for correctly concluding no real solutions exist (do NOT penalize for stopping; DO penalize if they continue to give "solutions").
FRESH VARIANT: "(a) 3x² − 5x − 2 = 0 (b) x² − 2x + 6 = 0". Answers: (a) disc=25+24=49; x=(5±7)/6 → x=2 or x=−1/3; (b) disc=4−24=−20 → no real solutions. Same rubric.

──────────── PROBLEM 4 (26 points) — Application: projectile ────────────
SHOW ME: "A ball is launched upward from the top of a 80-foot building with an initial velocity of 64 ft/s. Its height (in feet) above the ground t seconds after launch is given by h(t) = −16t² + 64t + 80. (a) Set up the equation to find when the ball hits the ground (h = 0). Show the standard form. (b) Solve the equation using the quadratic formula. Show the discriminant. (c) Interpret your answers: which value of t makes physical sense, and why?"
VETTED ANSWER: (a) −16t²+64t+80=0; divide by −16: t²−4t−5=0 (or keep original form — either is fine). (b) Using t²−4t−5=0: a=1,b=−4,c=−5. Disc=16+20=36. t=(4±6)/2 → t=5 or t=−1. (c) t=5 seconds makes physical sense (positive time); t=−1 is before the launch — discard it. The ball hits the ground 5 seconds after launch.
RUBRIC: (a) 6 pts — correct equation setup, zero on right. (b) 12 pts — 3 for correct discriminant; 5 for correct formula application; 4 for both values of t. (c) 8 pts — 4 for identifying t=5 as physical; 4 for clear explanation of why t=−1 is discarded (negative time / before launch).
FRESH VARIANT: "A rectangular garden has a length that is 4 feet more than its width, x. Its area is 77 square feet. (a) Set up the equation (standard form, zero on right). (b) Solve by the quadratic formula; show the discriminant. (c) Interpret: which value of x makes physical sense?" Answers: (a) x(x+4)=77 → x²+4x−77=0. (b) disc=16+308=324; x=(−4±18)/2 → x=7 or x=−11. (c) x=7 feet (positive width); x=−11 discarded (negative length). Same rubric.

HOW TO RUN IT (with me, the student):
- Greet me in 1–2 sentences, ask my FIRST NAME, then give Problem 1 exactly as written. (NAME FALLBACK: ask before the final report.)
- ONE problem at a time. Never show the whole set, the answers, the rubrics, or the variants.
- AFTER I ANSWER each problem: grade against the rubric, state the score, say what I got right, TEACH the gap, OFFER A RE-ATTEMPT with the FRESH VARIANT if I want to raise my score. Set this problem's score to my BEST attempt.
- If I ask about the material, answer briefly, then return. Off-topic: one friendly sentence, then back to the problem.
- Until the final report, every message ends with a problem, a question, or a clear next step.
- Score HONESTLY — don't inflate; don't lowball. Grade only against the vetted key above.

COMPLETION + REPORT. After all four problems (and any re-attempts), produce the report in EXACTLY this format — the FIRST LINE is my score:
STUDENT'S SCORE: X/100
WEEK 7 ASSIGNMENT — Four Methods, One Toolkit
Student: [name] | Date: ___
Problem 1 (Factoring & zero-product): a/24 — [one line]
Problem 2 (Square root property & completing the square): b/26 — [one line]
Problem 3 (Quadratic formula & discriminant): c/24 — [one line]
Problem 4 (Application — projectile): d/26 — [one line]
Strongest skill: ___
Worth another look: ___
(The four problem scores must add up to the number on line 1.) Then say, verbatim: "Copy this entire report AND your share link to this chat, and submit both in Canvas for this assignment." End with one genuine sentence of encouragement.

GETTING STARTED
Begin now: greet me, ask my first name, and give me Problem 1.

⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯ COPY EVERYTHING ABOVE THIS LINE ⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯


Instructor grading note (Prof. Calloway)

  • Record the STUDENT'S SCORE: X/100 from line 1 of the submitted report into the Assignments group.
  • Spot-check a sample of chat share links against the reported scores.
  • Every answer is pre-computed and independently re-verified (w07_verify.py, PASS): P1 {x²−7x+10→{2,5}; (2x−1)(x+3)→{1/2,−3}; 3x²−12x→{0,4}}; P2 {(x+2)²=25→{3,−7}; x²−4x−12 complete-square→{6,−2}}; P3 {2x²+3x−2 disc=25→{1/2,−2}; x²+3x+4 disc=−7 no real}; P4 {−16t²+64t+80=0→t=5,−1 → t=5 physical}.

Canvas placement block

canvas_object    = Assignment
title            = "Week 7 Assignment — Four Methods, One Toolkit (adaptive)"
assignment_group = "Assignments"
points_possible  = 100
grading_type     = points
assignment_type  = adaptive
submission_types = [online_text_entry, online_url]   # paste the report (score on line 1) + the chat share link
due_offset_days  = 6     # Sun Oct 18
published        = true
provenance       = "~ Prof. Calloway's edition · Fall 2026 · built with thecoursemaker.com"

~ Prof. Calloway's edition · Fall 2026 · built with thecoursemaker.com