Week 15 — Quiz (auto-graded) · Exponential & Logarithmic Equations & Applications
Course: College Algebra (MATH 120) · Silver Oak University (fictional sample) · Prof. Calloway
Objective tested: Objective 8 — solving exponential and logarithmic equations; growth, decay, and compound-interest applications.
Points: 10 (1 each) · Assignment group: Quizzes (15% of grade) · Due: end of Module 15.
This is the human-readable quiz with its vetted answer key and feedback. The import-ready Classic QTI is in
F-quiz-week-15-qti.xml. AI is not permitted on quizzes (course AI policy). Every numeric answer below is pre-computed and independently re-verified (Pythonw15_verify.py, PASS — 45 checks clean).
Blueprint
| # | Type | Concept | Objective |
|---|---|---|---|
| 1 | Multiple choice | Solve 2ˣ = 16 (same-base method) | 8 |
| 2 | Multiple choice | Solve 3^(x+1) = 27 (same-base method) | 8 |
| 3 | Multiple choice | Solve 5ˣ = 125 (same-base method) | 8 |
| 4 | Multiple choice | Solve 2ˣ = 10 (log of both sides; exact or decimal) | 8 |
| 5 | Multiple choice | Solve log₂(x) = 5 (convert to exponential) | 8 |
| 6 | Multiple choice | Solve log(x) = 2 (convert to exponential, base 10) | 8 |
| 7 | Multiple choice | Solve ln(x) = 0 | 8 |
| 8 | Multiple choice | Solve log₂(x − 1) = 3 (with domain check) | 8 |
| 9 | Multiple choice | Solve log(x) + log(x − 3) = 1 (extraneous solution) | 8 |
| 10 | Multiple choice | Doubling time at 6% continuous compounding | 8 |
No trick questions; distractors target the Week 15 misconceptions named in the lecture outline (treating exponents as multipliers; wrong log-of-both-sides step; accepting an extraneous log solution; application setup).
Questions, key, and feedback
Q1 (MC). Solve: 2ˣ = 16
- A. x = 8
- B. x = 4 ✅
- C. x = 14
- D. x = 32
Feedback: 16 = 2⁴, so 2ˣ = 2⁴ → x = 4 (equate exponents, same-base method). (A = 2·8, confusing base × exponent; C = 16 − 2; D = 2 × 16.)
Q2 (MC). Solve: 3^(x+1) = 27
- A. x = 1
- B. x = 2 ✅
- C. x = 8
- D. x = 3
Feedback: 27 = 3³, so 3^(x+1) = 3³ → x + 1 = 3 → x = 2. (A = solving 3·(x+1) = 27 incorrectly; C = treating exponent additively; D = confusing x with the exponent 3.)
Q3 (MC). Solve: 5ˣ = 125
- A. x = 25
- B. x = 120
- C. x = 3 ✅
- D. x = 625
Feedback: 125 = 5³, so 5ˣ = 5³ → x = 3. (A = 5²; B = 125 − 5; D = 5⁴.)
Q4 (MC). Solve: 2ˣ = 10 (give the exact expression or the best decimal approximation)
- A. x = 5
- B. x = 20
- C. x = log₂(10) ≈ 3.32 ✅
- D. x = log(10) = 1
Feedback: Take ln of both sides: x·ln 2 = ln 10 → x = ln(10)/ln(2) = log₂(10) ≈ 3.322. (A = 10/2; B = 10·2; D = log₁₀(10) = 1, ignoring the base-2 structure.)
Q5 (MC). Solve: log₂(x) = 5
- A. x = 10
- B. x = 32 ✅
- C. x = 5/2
- D. x = 25
Feedback: Convert: 2⁵ = x → x = 32. (A = base 10 confusion; C = 5÷2; D = 5².)
Q6 (MC). Solve: log x = 2 (log = base 10)
- A. x = 20
- B. x = 2/10
- C. x = 100 ✅
- D. x = 10
Feedback: Convert: 10² = x → x = 100. (A = 10·2; B = 2÷10; D = 10¹, confusing 1 for the given 2.)
Q7 (MC). Solve: ln x = 0
- A. x = 1 ✅
- B. x = 0
- C. x = e
- D. x = −1
Feedback: ln x = 0 means e⁰ = x → x = 1. (B = confusing ln(0); C = ln(e) = 1, not 0; D = undefined, ln of a negative.)
Q8 (MC). Solve: log₂(x − 1) = 3
- A. x = 7
- B. x = 9 ✅
- C. x = 4
- D. x = 2
Feedback: Convert: x − 1 = 2³ = 8 → x = 9. Domain check: x − 1 = 8 > 0. ✓ (A = 2³ − 1 = 7, but then 7+1 = 8 ≠ right setup; C = 2² + 1; D = 2¹ + 1.)
Q9 (MC). Solve: log x + log(x − 3) = 1 — select the valid solution only.
- A. x = −2 only
- B. x = 5 only ✅
- C. Both x = 5 and x = −2
- D. x = 8
Feedback: Condense: log[x(x−3)] = 1 → x(x−3) = 10 → x² − 3x − 10 = 0 → (x−5)(x+2) = 0. x = 5: log(5) and log(2) both defined ✓. x = −2: log(−2) undefined — extraneous. Answer: x = 5 only. (A = accepting the extraneous root; C = forgetting the domain check; D = arithmetic error.)
Q10 (MC). Money is invested at 6% interest compounded continuously. About how many years does it take to double?
- A. About 6 years
- B. About 8 years
- C. About 11.6 years ✅
- D. About 17 years
Feedback: A = Pe^(rt); doubling → 2 = e^(0.06t) → t = ln(2)/0.06 ≈ 11.55 years ≈ 11.6 yr. (A = 1/rate; B = 72/9 (wrong rate); D = ln(2)/0.04.)
Answer key (quick reference)
| Q | Answer |
|---|---|
| 1 | B (x = 4) |
| 2 | B (x = 2) |
| 3 | C (x = 3) |
| 4 | C (log₂(10) ≈ 3.32) |
| 5 | B (x = 32) |
| 6 | C (x = 100) |
| 7 | A (x = 1) |
| 8 | B (x = 9) |
| 9 | B (x = 5 only) |
| 10 | C (≈ 11.6 years) |
Quality gate (self-checked, computer-verified): each single-answer item has exactly one correct option. Arithmetic pre-computed and independently re-verified (w15_verify.py, PASS — 45 checks): Q1 2⁴=16; Q2 3³=27, x=2; Q3 5³=125; Q4 ln10/ln2≈3.322; Q5 2⁵=32; Q6 10²=100; Q7 e⁰=1; Q8 2³=8, x=9; Q9 x=5 valid (domain check), x=−2 extraneous; Q10 ln2/0.06≈11.55. All checks PASS. QTI parse confirmation: F-quiz-week-15-qti.xml generated and confirmed "parses OK, 10 items."
Item-bank entries (for variants + the final)
All ten items are tagged course=MATH120 · week=15 · objective=8 · topic=exp-log-equations-applications and deposited in Item Bank: Week 15 — Exponential & Logarithmic Equations & Applications. The final (Week 16) draws Objective 8 items from this bank. (Tags: q1 same-base, q2 same-base-linear-exp, q3 same-base, q4 log-both-sides, q5 log-to-exp, q6 log-to-exp-base10, q7 ln-to-exp, q8 log-to-exp-domain, q9 extraneous-log, q10 doubling-time.)
Canvas placement block
canvas_object = Quizzes::Quiz
title = "Week 15 Quiz — Exponential & Logarithmic Equations & Applications"
assignment_group = "Quizzes"
points_possible = 10
grading_type = points
due_offset_days = 6 # 6 days after module start (Sun Dec 13)
published = true
shuffle_answers = true
provenance = "~ Prof. Calloway's edition · Fall 2026 · built with thecoursemaker.com"
F-quiz-week-15-qti.xml) ships inside the course's .imscc package — it lands in the Canvas gradebook on import.~ Prof. Calloway's edition · Fall 2026 · built with thecoursemaker.com