Week 2 Quiz

To solve 3(x − 2) = 2x + 5, you first distribute the 3. Which equation do you get?

Select one.

• 3x − 2 = 2x + 5
• 3x − 6 = 2x + 5
• 3x + 6 = 2x + 5
• x − 6 = 2x + 5

Solve 3(x − 2) = 2x + 5. Enter the value of x as a whole number only.

Type a short answer.

To clear the fractions in x ⁄ 2 + 1 ⁄ 3 = 5 ⁄ 6, you multiply every term by the LCD, 6. Which equation do you get?

Select one.

• 3x + 2 = 5 ⁄ 6
• x + 2 = 5
• 3x + 1 = 5
• 3x + 2 = 5

Solving 2(x + 3) − 3 = 2x + 7 leads to the statement 3 = 7 once the x terms cancel. What is the solution set?

Select one.

• No solution
• All real numbers
• x = 0
• x = 3

Solve −2x + 1 < 9 and write the solution set in interval notation.

Select one.

• (−∞, −4)
• [−4, ∞)
• (−4, ∞)
• (−4, ∞]

Solve −3x > 9.

Select one.

• x > −3
• x < 3
• x > 3
• x < −3

Select every value of x that is a solution of |2x − 1| = 7.

Select every option that applies.

• 4
• −3
• 3
• −4
• 7

The equation |x| = −5 has no solution, because absolute value measures a distance from 0 and a distance is never negative.

True or false.

• True
• False

Which interval notation describes every x with |x| ≥ 3?

Select one.

• (−∞, −3] ∪ [3, ∞)
• [−3, 3]
• (−∞, −3) ∪ (3, ∞)
• (−3, 3)

To check x = 11 in 3(x − 2) = 2x + 5, you evaluate the left side, 3(11 − 2), using the order of operations. What value do you get?

Select one.

• 31
• 33
• 27
• 9