Week 9 Quiz
What is the vertex of the parabola f(x) = (x + 3)² − 5?
Select one.
- (3, −5)
- (−3, −5)
- (−3, 5)
- (3, 5)
Use the vertex formula h = −b ⁄ (2a) to find the vertex of the week's parabola f(x) = x² − 6x + 5.
Select one.
- (−3, 32)
- (0, 5)
- (3, −4)
- (6, 5)
The parabola f(x) = −x² + 4x + 1 has a = −1, b = 4, and c = 1. Which statement gives its vertex and says what kind of value the vertex is?
Select one.
- (2, 5), a maximum value
- (2, 5), a minimum value
- (−2, −11), a maximum value
- (2, 13), a maximum value
The parabola f(x) = (x − 2)² + 3 expands to x² − 4x + 7. How many x-intercepts does it have?
Select one.
- Two, because the discriminant 16 + 28 = 44 is positive
- One, because the vertex (2, 3) is a single point
- Two, because a = 1 is positive
- None, because the discriminant 16 − 28 = −12 is negative
What is the y-intercept of the week's parabola f(x) = x² − 6x + 5?
Select one.
- (0, −4)
- (0, 5)
- (0, 1)
- (5, 0)
The week's parabola f(x) = x² − 6x + 5 has vertex (3, −4) and a = 1. What is its range?
Select one.
- [−4, ∞)
- (−∞, −4]
- [3, ∞)
- [5, ∞)
For the week's parabola, f(2) = −3, and the axis of symmetry is x = 3. Which other input x gives f(x) = −3?
Select one.
- −2
- 3
- 4
- 8
Which is the standard form of f(x) = 2(x − 1)² − 3?
Select one.
- 2x² − 5
- 4x² − 8x + 1
- 2x² − 2x − 1
- 2x² − 4x − 1
A launched object's height in feet t seconds after launch is h(t) = −16t² + 64t + 80. When does it reach its greatest height, and how high is that?
Select one.
- After 2 seconds, at 144 feet
- After 5 seconds, at 0 feet
- At the moment of launch, at a height of 80 feet
- After 2 seconds, at 80 feet
A rectangular garden is surrounded by 40 feet of fencing, so its area is A(w) = w(20 − w) = −w² + 20w square feet for a width of w feet. Which width gives the largest area, and what is that area?
Select one.
- A width of 20 feet, for 400 square feet
- A width of 10 feet, for 100 square feet
- A width of 12 feet, for 96 square feet
- A width of 5 feet, for an area of 75 square feet
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